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CE-T Analog Electrical transducer
Product Range Selection Guide Overview Notice
CE-IJ03 / CE-IJ03A
PRODUCT: 1 ELEMENT AC CURRENT TRANSDUCER
SERIES: CE-IJ03
CE-IJ03A (TRUE RMS)
INPUT RANGE: 0.5A~300A
OUTPUT: 5V or 4-20 mA
ACCURACY: 0.2% or 0.5%
RESPONSE TIME: 300 mS
POWER SOURCE: +12V or +15V or +24V
LOAD CAPABILITY: Voltage Output ³2kW
Current Output£250W
QUISCENT POWER CONSUMPTION: £ 300 mW
Specifications
CE-IJ03
CE-IJ03 / CE-IJ03A
CE-IJ03 / CE-IJ03A
CE-IJ03 / CE-IJ03A
SERIES OPERATING PRINCIPLE ISOLATION VOLTAGE RESPONSE TIME (ms) OVERLOAD CAPABILITY Quiescent Power(mW)> MOUNTING
Vz,Vd,Vg,Iz Output Iy Output
CE-IJ03 Electromagnetic £2500VDC £400ms The minor of 20 times or 500A 5/sec 180 (0.2% accuracy) 300 (0.2%) DIN Rail or PCB
CE-IJ03A 200(0.5% accuracy) 250(0.5%)

 

Series Output Power Source Window (mm) Case Style Accuracy
% 		Rated Input
CE-IJ03 3: 0~5V DC(Vz)
8: 0~10V DC(Vd)
 2---12V
3---15V
 B--F6.5 H1
 0.5 0.5A,1A,5A,10A,15A,25A
CE-IJ03
CE-IJ03A
1: 0~5V RMS(Vg)*
3: 0~5V DC(Vz)
4: 0~20 mA(Iz)
5: 4~20 mA(Iy)**
7: 4~20 mA(Id)***
8: 0~10V DC(Vd)		 2---12V
3---15V
4---24V		 M--no window S2 0.2
0.5		 0.5A,1A,5A
5A,10A,15A,25A
B--F6.5
D--F13 S3 30A,50A,75A,100A,
E--F20 0.5 120A,150A,200A,250A,300A

Part Number Example: CE-IJ03-32BS2-O.5/0~5A
Description: 1 element AC Current Transducer, average responding, Input: 0~5Aac Output: 0~5Vdc, Power source: +12Vdc, Window: F 6.5mm, Accuracy: 0.5%, Case style: S2

1 Explain for Code

Code 1 3 4 5 6 7 8
Symbol Vg Vz Iz Iy Vy Id Vd
Definition Tracking Voltage Output DC Voltage Output DC Current Output DC Current Output DC Voltage Output 2-wire DC Current DC Voltage Output

2 Explain for
* Loop resistance from 0 to 250W. Contact factory for loop resistance above 250 O
Applications

Applications for CE-IJ03:

  • Multi-point current sensing and control panels
  • Monitor lighting elements
  • Monitor heating elements
  • Remote current sensing
  • Monitor motor faults

Applications for CE-IJ03A:

  • Sub-metering Energy Measurement
  • Motor Loads
  • Remote Monitoring
  • Automatic Control Systems
  • Loading Shedding

    Note:
  • The size of window must be fit for the conducting wire to pass through. When the rated current £5A, you can use terminal input.
  • All connections of the positive and negative polarities must be right. The output signal and the power source must be grounded in common.
 
     
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